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When posting your question please:- Choose the correct forum for your message. Posting a VB.NET question in the C++ forum will end in tears.
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Insults, slap-downs and sarcasm aren't welcome. Let's work to help developers, not make them feel stupid.
cheers,
Chris Maunder
The Code Project Co-founder
Microsoft C++ MVP
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For example this packages I need to install but it has 154 Packages. How to install all of them ?
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You're going to have to go into more detail. I have never heard of such a situation where an app needs so many packages.
You can only install one package at a time. There is no way to select a vendor and say "install everything" or even select more than one package and install it.
To install 154 packages, you would have to write a Powershell script or batch file, with all the appropriate command lines and execute it to get all those packages installed.
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Ok thanks. I was testing a vendor components and wanted all the components available to me
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I can not open the old form again. I get this error:
Timed out while connecting to named pipe
Picture:
https://learn-attachment.microsoft.com/api/attachments/201941-image-14-05-22-at-723-am.jpg?platform=QnA[^]
I searched and followed some steps but without solution
- Disabled my firewall
- Change warning level to none in the options of "Windows Forms Designer"
- Changed target .Net from net8 to net7
- Deleted .vs, obj , bin
- Creating new form also result in the same problem
Any other solution ? I use VS 2022 community
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Try this:
Go to Tools menu and click Options. In the dialog, in the upper-left corner of the window, type "preview". In the list of items that shows up on the left, click On Preview Features. In the right side of the window, UNCHECK the "Use the preview Windows Forms out-of-process designer..." option. Click OK and restart Visual Studio.
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I get now this error:
An error occurred in 'myproject' while attempting to open 'Form1.cs [Design]'
Value does not fall within the expected range.
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I changed target framework to net471 then save, reload then change it back to net8-windows then save, close VS and open the project again and now the form loaded normally !!!
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Using Visual Studio 2022 latest build. EDIT: This is not a .NET Framework project, it's a .NET core Windows Forms project, or whatever it's called.
I have a situation where I've added a bunch of controls to a form, but Visual Studio is not updating the Designer.cs file with the new controls. The controls all exist as I placed them on design canvas, but when I compile the project, the controls don't appear in the EXE because the Designer.cs file is not synchronized with the canvas.
Question: How can I force Visual Studio to rewrite the Designer.cs file so that all the controls that I added are accounted for? I'd rather not remove the form from the project and add it back because I'd lose all the work I did to place the controls.
Any assistance is greatly appreciated!
SOLUTION:
I was able to fix it by removing the project from the solution and then adding it back.
The difficult we do right away...
...the impossible takes slightly longer.
modified 8-Jul-23 18:32pm.
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Yip, removing the project (or whatever it's called  ) from the solution and then adding it back will do the trick. I just had to throw this in here lol.
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Hello,
I have two windows forms, form1 and form2. I have placed a button on form1. When I click the button on form1 it will open up form2 via
new Form2().Showdialog()
I have added 2 buttons to my form2 and a serialport. My 2 buttons are called Connect and Disconnect on form2. When I click the Connect button my comm port opens using
serialport1.open() . When I click Disconnect the port closes using
serialport1.close(). This all works fine until I click
serialport1.open then close form2 then open form2 via my form1 button again. Keeping in mind that the port is still open or that's my hopes, when I press Disconnect on my form2 my port will not close.
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I can think of 2 possibilities:
1. Put the serial port code in a handler class that implements IDisposable and pass it to form2 in the constructor:
Using serialHandler As New SerialHandler
Dim form2 As Form2 = New Form2(serialHandler)
form2().Showdialog()
End Using
The Dispose method on the SerialHandler will handle the closing of the serial port if not already closed and dispose of any object that may cause memory leaks.
The other benefit is that you have encapsulated serial port handling and simplified Form2's code.
Note: If not modal, then store a reference to SerialHandler in Form1 and manually call the Dispose method of the SerialHandler class when Form2 is closed - this will require listening for Form2 closing event.
2. Implement IDisposable in Form2 so that when the form is closed and disposed of, the same applies as the first case.
If it was me, I would use Option 1.
Graeme
"I fear not the man who has practiced ten thousand kicks one time, but I fear the man that has practiced one kick ten thousand times!" - Bruce Lee
modified 23-Mar-23 21:18pm.
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Thank you MUCH! Are you C# uhm what's the word? Fluent maybe? When I think of serial handler I think of a receive event handler for the serial port. So I'm a little lost on VB.
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Your code presented as VB, so I replied in kind. C# works the same with minor variances.
Graeme
"I fear not the man who has practiced ten thousand kicks one time, but I fear the man that has practiced one kick ten thousand times!" - Bruce Lee
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hello
I have a viewer that displays image files in wimforms. I run it from another external software and pass it file data for display in parameters to main args[].
Every time when I call the viewer I want to open the same process in order to immediately open the viewer and not close and restart.
I successful to identify the current running process and also enlarge the same Form window,
but I don't know how to perform show new Form again, So that the viewer will update the view with new files.
I mean , i have current class Process . but i need to execute Application.Run(new Form) but for current process
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You don't need to run Application.Run again. What you do need to do is setup some kind of communication channel where the first instance of your app is listening for messages from a second instance. You can launch a second instance of your display app and when it detects that the first instance is already running, send a message over the channel so the first instance can be told what to do, like load a different file and display it.
One method of doing this is to use IpcChannel[^]
You can use a Mutex[^] to determine if your app is already running.
modified 16-Jan-23 22:04pm.
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my code
If DataGridView1.Rows.Count - 1 Then
DataGridView1.Rows.Add()
DataGridView1.CurrentCell = DataGridView1.Rows(DataGridView1.Rows.Count - 1).Cells(1)
DataGridView1.BeginEdit(True)
Else
Exit Sub
' DataGridView1.Rows.Add()
End If
i many code try
If (DataGridView1.Rows.Count > 0) Then
For i = 0 To DataGridView1.Rows.Count - 1
If DataGridView1.Rows(i).Cells("d1alisname").Value = "" Then
Exit Sub
Else
DataGridView1.Rows.Add()
End If
Next
End If
but add row
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So what exactly is the problem?
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Sufvan Adil 2023 wrote:
If DataGridView1.Rows.Count - 1 Then
Thanks to VB's "evil type coercion", that condition will be False if you have precisely one row in your grid. For any other number of rows, that condition will be True.
Sufvan Adil 2023 wrote:
For i = 0 To DataGridView1.Rows.Count - 1
If DataGridView1.Rows(i).Cells("d1alisname").Value = "" Then
Exit Sub
Else
DataGridView1.Rows.Add()
End If
Next
That code walks through all the rows in your grid until it finds one where the d1alisname column is blank. For every row that it encounters where that column is not blank, it adds a new row.
You haven't explained exactly what you're trying to do. At a guess, you want to add a new row if there are either no rows in the grid, or all of the rows have a value in the d1alisname column. In which case, you need to move the "add row" code after your For loop from your second code block:
For i = 0 To DataGridView1.Rows.Count - 1
If DataGridView1.Rows(i).Cells("d1alisname").Value = "" Then
Exit Sub
End If
Next
DataGridView1.Rows.Add()
"These people looked deep within my soul and assigned me a number based on the order in which I joined."
- Homer
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The following problem: Chart x-axis represents calendar weeks from 2021/35 to 2022/36 (current week 2022/19). I don't want to represent every week as a label, but only every 5th week. Up to the current week it looks relatively good, but after that every week is displayed as label.
newchart(chart1)
Dim chartArea1 As New ChartArea("Default")
chart1.AntiAliasing = AntiAliasingStyles.None
chart1.TextAntiAliasingQuality = TextAntiAliasingQuality.Normal
chart1.ChartAreas.Add(chartArea1)
chart1.ChartAreas("Default").CursorX.IsUserEnabled = False
chart1.ChartAreas("Default").CursorX.IsUserSelectionEnabled = False
chart1.ChartAreas("Default").BackGradientStyle = GradientStyle.None
chart1.ChartAreas("Default").Position.Auto = False
chart1.ChartAreas("Default").Position.X = 0
chart1.ChartAreas("Default").Position.Y = 10
chart1.ChartAreas("Default").Position.Width = ChartAreasWidth
chart1.ChartAreas("Default").Position.Height = ChartAreasHeight - 4
chart1.ChartAreas("Default").AxisX.ScaleView.Zoomable = True
chart1.ChartAreas("Default").AxisX.ScrollBar.IsPositionedInside = True
chart1.ChartAreas("Default").AxisX.MajorGrid.Enabled = False
chart1.ChartAreas("Default").AxisX.MajorGrid.LineWidth = 1
chart1.ChartAreas("Default").AxisX.IntervalType = DateTimeIntervalType.Weeks
chart1.ChartAreas("Default").AxisX.Interval = 1
chart1.ChartAreas("Default").AxisX.LabelAutoFitStyle = LabelAutoFitStyles.DecreaseFont
chart1.ChartAreas("Default").AxisX.LabelAutoFitMinFontSize = 7
chart1.ChartAreas("Default").AxisX.LabelStyle.Font = My.Settings.fontbold8
chart1.ChartAreas("Default").AxisX.LabelStyle.Angle = 90
chart1.ChartAreas("Default").AxisX.MajorTickMark.Enabled = True
chart1.ChartAreas("Default").AxisX.MinorTickMark.Enabled = False
chart1.ChartAreas("Default").AxisX.Minimum = von_X.ToOADate()
chart1.ChartAreas("Default").AxisX.Maximum = bis_X.ToOADate()
chart1.ChartAreas("Default").AxisX.IsMarginVisible = False
chart1.ChartAreas("Default").AxisY.MinorTickMark.Enabled = True
chart1.ChartAreas("Default").AxisY.MinorTickMark.TickMarkStyle = TickMarkStyle.InsideArea
chart1.ChartAreas("Default").AxisY.MajorGrid.LineWidth = 1
chart1.ChartAreas("Default").AxisY.MajorGrid.LineColor = Color.Black
chart1.ChartAreas("Default").AxisY.LabelStyle.Font = My.Settings.fontbold8
chart1.ChartAreas("Default").AxisY.LabelStyle.Format = "C0"
chart1.ChartAreas("Default").AxisY.LabelAutoFitStyle = LabelAutoFitStyles.DecreaseFont
chart1.ChartAreas("Default").AxisY.LabelAutoFitMinFontSize = 7
chart1.ChartAreas("Default").AxisY.Minimum = 0
chart1.ChartAreas("Default").AxisY2.LineDashStyle = ChartDashStyle.Solid
chart1.ChartAreas("Default").AxisY2.LineWidth = 1
chart1.ChartAreas("Default").AxisY2.LineColor = Color.Black
chart1.ChartAreas("Default").AxisY2.Enabled = AxisEnabled.True
chart1.ChartAreas("Default").AxisY2.MajorTickMark.Enabled = False
chart1.ChartAreas("Default").AxisY2.LabelStyle.ForeColor = Color.Transparent
chart1.ChartAreas("Default").AxisY2.LabelStyle.Font = My.Settings.fontbold8
chart1.ChartAreas("Default").AxisY2.MajorGrid.Enabled = False
chart1.ChartAreas("Default").AxisY2.LabelAutoFitStyle = LabelAutoFitStyles.DecreaseFont
chart1.ChartAreas("Default").AxisY2.LabelAutoFitMinFontSize = 7
chart1.ChartAreas("Default").BackColor = Color.White
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There is no option to do this automatically.
You would have to go through the Series Points collection and clear the AxisLabel property of every data point you do not want to have a label.
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You should be able to specify which column to use for Labels. Add an extra "label" column to your data and blank out the first 4 in every 5.
"Before entering on an understanding, I have meditated for a long time, and have foreseen what might happen. It is not genius which reveals to me suddenly, secretly, what I have to say or to do in a circumstance unexpected by other people; it is reflection, it is meditation." - Napoleon I
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