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Comments by Richard Deeming (Top 200 by date)

Richard Deeming 21hrs ago View    
"It sort-of works but not quite" is NOT the same as "it works".

You have posted a solution which asks for more help. That is not a solution.
Richard Deeming 5 days ago View    
So some code that doesn't work, and doesn't do what you want, is not only "a solution" to your question, it is "THE solution" to your question?!

Remove this non-solution, and update your question instead.
Richard Deeming 5 days ago View    
Given the OP's profile name matches a brand of Indian hair-care products, I'm fully expecting a spam link to appear soon.
Richard Deeming 5 days ago View    
Better yet, check the documentation:
.ready() | jQuery API Documentation[^]

Specifically the following remarks:

jQuery offers several ways to attach a function that will run when the DOM is ready. All of the following syntaxes are equivalent:

* $( handler )
* $( document ).ready( handler )
* $( "document" ).ready( handler )
* $( "img" ).ready( handler )
* $().ready( handler )

As of jQuery 3.0, only the first syntax is recommended; the other syntaxes still work but are deprecated.

So instead of:
$(document).ready(function () { ... });

use:
$(function () { ... });
Richard Deeming 14-May-24 10:06am View    
In what way does the DataGrid control not "substitute the DataGridView"?

If you want recommendations for a control with specific features, then you need to provide details of the features you're looking for.